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In 1997,Andrew Beal conjectured that if A=B=C=1,m,n,r are all larger than 2,the equation has not positive integers solution. 1997年;Andrew Beal猜想:如果A=B=C=1;m;n;r均大于2;则该方程没有正整数解.
Let r be an odd integer with r>1.In this paper the author gives a necessary condition for(X,Y,Z) being a positive integer solution of the equation X~2+Y~2=Z~r with Y being a power of an odd prime. 设r是大于1的奇数;给出了方程X2+Y2=Zr的正整数解(X;Y;Z)中Y为奇素数方幂的必要条件.
Let(a,b,c) be a primitive Pythagorean triple with a is even. In this paper we prove that if c is a prime power,then the equation x~2+b~y=c~z has only the positive integer solution(x,y,z)=(a,2,2) with y is even. 设(a;b;c)是一组适合a为偶数的本原商高数;该文证明了:当c是素数方幂时;方程x2+by=cz仅有正整数解(x;y;z)=(a;2;2)可使y是偶数.
In this paper, let p be an odd prime with p>3, we prove that the equation (xp-yp)/(x-y)=z2 has only the positive integer solution (x, y, z, p)=(3,1,11,5), satisfying x>y+1. gcd (x, y)=1. As a result, x is an odd prime power. 设p是大于3的奇素数,证明:方程2)()(zyxyxpp=--,1+>yx,1),gcd(=yx仅当p=5时有正整数解)11,1,3(),,(=zyx可使x是奇素数的方幂。
Using the elementary methods, all the positive integer solutions of the equation are obtained.The solvability of the equation is solved completely. 利用初等方法，获得了方程的所有正整数解，完全解决了该方程的可解性问题。
number of positive integer solution 正整数解数
It is proved that if p>3 and D is not divisible by p or primes of the form 2kp+1,then the equation x~p-2~p=pDy~2 has no positive integer solutions (x,y) with gcd (x,y)=1. 本文证明了:当p>3时;如果D不能被p或2kp+1之形素数整除;则方程xp-2p=pDy2没有适合gcd(x;y)=1的正整数解(x;y).
Please enter positive integers only. 请只输入正整数。
Of or relating to positive integers. 自然数的属于或和自然数有关的
Let x,n be positive integers,and let p be a prim e. 单位：茂名教育学院数学系广东茂名525000;
positive integers solution 正整数解
The Positive Integer Solution to a Class of Diophantine Equations 一类丢番图方程的正整数解
A good choice for unique identifiers is to use positive integers. 正整数非常适合于用作唯一标识符。
Let s,t be positive integers with gcd (s,t) = 1, s > t. 设s,t满足gcd(s,t)=1,s>t的正整数,a=2st,b=s~2-t~2,c=s~2+t~2。
That can be put into a one-to-one correspondence with the positive integers. 可数的与正整数有一对一的对应关系的；可数的
Subscript indices must either be real positive integers or logicals. 下标指标必须或者是真实的积极的整数逻辑。
LAST INTEGER SOLUTION IS THE BEST FOUND! 以上整数解是最优解!
How many four-digit positive integers have their product of digits even? 数字之积为偶数的四位正整数共有多少个?
Capable of being put into one-to-one correspondence with the positive integers; countable. 可数的能够用正数一个一个地表示出来的；可数的
Please enter a positive integer. 请输入正整数。

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