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- admissible subalgebra 容许子代数
- To be admissible or maintainable. 可容许的或可保留的
- Such behaviour is not admissible among our staff. 这种行为在我们职员中是不允许的.
- The court ruled that the evidence was admissible. 法院裁决说证据可以接受。
- IS SUBALGEBRA GENERATED BY NILPOTENT ELEMENTS NILPOTENT_? 幂零元生成的子代数是幂零吗?
- A doctrine contending that sense perceptions are the only admissible basis of human knowledge and precise thought. 实证主义认为感官的感知是人类知识及精确思维唯一可允许的基础的主义
- The documentary or oral statements and the material objects admissible as testimony in a court of law. 证词，证据法庭上作为证据的文件或口头形式的陈述和实物
- I wonder whether I am admissible to the program or not. 我想知道我是否能被录取。
- Evidence based on the reports of others rather than the personal knowledge of a witness and therefore generally not admissible as testimony. 传闻证据证人根据别人讲述的内容而不是本人所了解的情况作出的证词，因此一向不作为可接受的证据
- An unsworn statement of facts that is admissible as evidence. 陈述，证词指没有立誓的证明，所述事实可作为证据
- But such stress tests are beatable and not admissible in court. 但是这样的压力测试并不可靠，而且在法庭上不允许使用。
- Co. and [CYD] Co. and it is not admissible as evidence. 公司与[CYD]公司的草拟合同不具有真实性、排他性，不可作为证据使用。
- Any decision of the DAB shall be admissible in evidence in the arbitration. 在仲裁过程中，可将争端裁决委员会的决定作为一项证据。
- Conclusion Every fuzzy subalgebra of a fuzzy P-semisimple BCI-alegbras is also a fuzzy P-semisimple BCI-algebras. 结论说明任一模糊P-半单BCI代数的模糊子代数，也是模糊P-半单BCI-代数。
- On January 29th the European court declared that the Yukos case was admissible. 1月29日，欧洲法院宣布，受理尤科斯案。
- We recommend that you test the maximum admissible bitrate for each player. 我们建议您测试可能用到的每一款影碟机能够接受的最大码率。
- In this paper, we study the subalgebra structure of the general linear Lie algebras over commutative rings. 摘要本文研究了含幺可换环上一般线性李代数的子代数结构。
- A study is made of admissible number of preference profile with transitivity. 对具有传递性的偏好断面规模问题进行研究。
- Also we proved that any proper subalgebra of a standardKac-Moody algebra g(A) is standard, where A1 is any principle submatrix of A (see Theorem 2.6). 证明了典范Kac-Moody代数g(A)的任一真子代数g(A_1)也是典范的，此处A_1是A的任一主子阵(定理2.;6)。
- It is proved that the Frattini subalgebra of a complete Lie algebra with abelian nilpotent radical is the zero subalgebra. 证明了特征零代数闭域上的具有交换幂零根基的完备Lie代数的Fratini子代数为零。
